Question

The product of the zeros of the polynomials 2x^2+3x+1 is​

Answer 1

2x^2+3x+1

2x^2+2x+x+1

2x(x+1)+1(x+1)

(2x+1)(x+1)

hence (2x+1)(x+1)is the product of 2x^2+3x+1

Answer 2

$\small\red{\underline{Question } = } \\\small\red{\underline{the \: product \: of \: the \: zeros \: of \: the \: polynomial}}$

$\small\red{\underline{\underline{Question } = }} \\\small\red{\underline{the \: product \: of \: the \: zeros \: of \: the \: polynomial}}\\ \small\red{\underline{2 {x}^{2} + 3x + 1 \: \: }is.} \\ \\ \small\orange{\underline{\underline{solution}}} \\ \\ \color{blue} 2 {x}^{2} + 3x + 1 = 0 \\ \\ \color{blue} 2 {x}^{2} + (2 + 1)x + 1 = 0 \\ \\ \color{blue}2 {x}^{2} + 2x + x + 1 = 0\\ \\ \color{blue}2x(x + 1) + 1(x + 1) = 0 \\ \\\color{blue} (2 {x} + 1)(x + 1) = 0 \\ \\ \color{blue}2x + 1 = 0 \: \: , \: \: x + 1 = 0\\ \\ \color{blue}2x = - 1 \: \: , \: \: x = - 1\\ \\ \small\green{\boxed{ \boxed{x = \frac{ - 1}{2} \: \: , \: \: x = - 1 } \: is \: the \: answer}}\\ \\\small\green{\underline{ zeros \: of \: the \: polynomial \: is \: \: \frac{ - 1}{2} \: and \: - 1 \: \: .}} \\ \\ \small\pink{\boxed{hope \: its \: help \: you \: dear}} \\ \\ \small\red{\boxed{\boxed{it's ᭄亗 乄 ＭꫝղᎥនh 乄 亗✯❤࿐}}}$