Question

The product of the zeros of x²-15 is

Answer 1

$for \\ a {x}^{2} + bx + c = 0 \\ \\ if \: \alpha \: \: \beta \: are \: roots \: \: then \\ \\ \alpha + \beta = - \frac{b}{a} \\ \\ \alpha \beta = \frac{c}{a} \\ \\ now \: here \: \\ \\ \alpha + \beta = 0 \\ \\ \alpha \beta = - 15$

hope it helps

Answer 2

Answer:

Step-by-step explanation:

For