Question

The product of three consecutive even integers is 480. What is the sum of the integers ?​

Answer 1

Step-by-step explanation:

Let the three terms be a - d, a, a + d

Sum = 24                  Product = 480

∴a−/d+a+a+/d=24

3a=24

∴a=8

(a−d)(a)(a+d)=480

(8−d)(8)(8+d)=480[∵a=8]

(8−d)(8+d)=60

64−d2=60

d2=±4=±2

If a=8,d=2 the terms are 

a−d=8−2=6,a=8,a+d=8+2=10

∴ the term are 6,8,10.

We will get the same values if we'll consider d=−2.