Question

The product of three consecutive numbers is always divisible by 6. Prove this statement with the help of counter example

Answer 1

Answer:

Let three consecutive positive integers be, n, n + 1 and n + 2. Whenever a number is divided by 3, the remainder obtained is either 0 or 1 or 2. ∴ n = 3p or 3p + 1 or 3p + 2, where p is some integer. If n = 3p, then n is divisible by 3.

Answer 2

Answer:

Yes it is true.

Step-by-step explanation:

Consider If you have 3 consecutive natural numbers, then at least 1 of them must be divisible by 2, and 1 of them must be divisible by 3. hence, their product must always be divisible by 2x3=6.