Math, asked by Esha7510, 1 year ago

The product of three consecutive positive integers is 8 times their sum. What is the sum of their squares?

Answers

Answered by rahman786khalilu
4

by solving we get the answer

Attachments:
Answered by mkrishnan
2
let x-1,x,x+1 are 3 consecutive positive numbers

given

product = 8(sum)

( x -1)x(x+1) =8(3x)

x(x^2-1) =24x

x can not 0

x^2-1=24

x^2=25

x=5

the numbers 4,5,6
sum of squares
16+25+36=77
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