The product of three consecutive terms of a G.P. is 512. If 4 is added to each of the first and the second of these terms, the three terms now form an A.P. Then the sum of the original three terms of the given G.P. is:
(A) 36 (B) 32
(C) 24 (D) 28
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Answer:
28.
Step-by-step explanation:
Let the three terms of the G.P be:
› a/r, a, ar
According to the question:
› a/r × a × ar = 512
› a³ = 512
› a = ³√512
∴ a = 8
4 is added to each of the first and the second of these terms, the three terms now form an A.P.
› 8/r + 4, 8 + 4, 8r.
∵ 8/r + 4, 8 + 4, 8r from an A.P.
› 2 × 12 = 8/r + 8r + 4
› 2r² - 5r + 2 = 0
› (2r - 1) (r - 2) = 0
› r = 1/2 or 2.
Sum of three terms of the given G.P:
› 8/2 + 8 + 16
∴ 28
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