Question

the product of three consecutive terms of a geometric progression is 343 and their sum is 9/3 . find the three terms​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

Let the three consecutive terms of gp be a/r,a,ar

Given that :

a/r.a.ar =343

a^3 = 343

a.a.a=7.7.7

a=7

a/r +a + ar =9/3

a + ar +ar^2 / r = 9/3

a(r^2 + r + 1)/r = 3

7(r^2 + r + 1)/r = 3

(r^2 + r + 1)/r = 3/7

(r^2 + r + 1) = 3r/7

7r^2 +7r + 7= 3r

7r^2 + 4r + 7= 0