The product of three integers is (−85). If the two integers are (−17) and (−5), find the third
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1
Integers are just whole numbers: positive, negative, and zero.
I = {-∞,...,-3, -2, -1, 0, 1, 2, 3, ..., ∞}
Let x = 1st integer
Let y = 2nd integer
x = 3y + 17 {equation 1}
xy = -24 {equation 2}
Substitute 3y+17 in place of x n equation 2
and solve for y.
(3y+17)y = -24
3y2 + 17y = -24
3y2 + 17y + 24 = 0
From quadratic equation:
y = [-17±√(172-4(3)(24))]/(2(3))
y = (-17 ±√1)/6
y = (-17+1)/6 or y = (-17-1)/6
y = -16/6 or y = -18/6
y = -2 2/3 or y = -3
Since we are dealing with integers...
y = -3
x = 3y+17 = -9+17 = 8
The integers are -3, 8
Answered by
2
Answer:
let the third integer be x
so (x)*(-17)*(-5)=-85
=>(x)(85)=-85
=>x= -85/85
=>x= -1
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