Question

the product of three numbers in an AP is 280 and their sum is 21find the numbers​

Answer 1

Answer:

4,7,10

Step-by-step explanation:

that is just hit and try

Answer 2

Answer:

4 , 7 and 10

Step-by-step explanation:

Let the numbers be a -d , a and a+d

According to question,

Sum of all numbers = 21

=> a -d + a + a + d = 21

=> 3a = 21

=> a = 7

Now,

Product of numbers = 280

=> (a-d)(a)(a+d) = 280

=> (a^2 - d^2) 7 = 280

=> ( 49 - d^2) = 40

=> 9 = d^2

=> d = 3

Required numbers are 4 , 7 and 10