The product of three numbers is 71/2. If two of them are 11\7 and 33/4, find the third number.
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Atoms form chemical bonds to make their outer electron shells more stable. The type of chemical bond maximizes the stability of the atoms that form it.
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Answer:
product of two numbers is 71/2
one number = 11/7
second number = 33/4
so the required number = 11/7+ 33/4 = 71/2
take the lcm of 7 and 4 = 28
= 44 +231 /28 = 71/2
= 275/28 = 71/2
= 71/2 -275/28
= 994-275 / 28
= 722/ 28
= 351 / 14 ( after cutting it by 2)
= 2 whole 71 / 14 ( after changing it in misted fraction)
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