Question

The product of three numbers is 7980. In
which the product of two numbers is 228,
then what is the third number? UNV 2007]​

Answer 1

Step-by-step explanation:

With other answers approaching it algebraically, I decided to approach it somewhat differently.

19600 = 100 * 196 = 2 * 5 * 2 * 5 * 2 * 7 * 2 * 7 (prime factorization).

Now 10 = 2 * 5, and 24 = 2 * 2 * 2 * 3.

Division can be looked on as the removal of common factors.

I can remove 4 2s and a 5. That leaves 5 * 7 * 7, but I still have a factor of 3 that needs to be removed. So obviously, the result will not be an integer.

So the third number is 245/3.