Question

the product of three terms of an ap is 1620 and their sum is 36 find the AP​

Answer 1

Answer:

Think that the first three terms are x, y, z and do

Step-by-step explanation:

Answer 2

ap roots are (a+d),a,a-d

a+d+a+a-d= 36

3a=36

a=12

(a+d)(a)(a-d)=1620

(12+d)(12)(12-d)=1620

(12+d)(12-d)=135

${a - b} \: \: {a + b} = {a}^{2} - {b}^{2}$

12^2 -d^2=135

-d^2 =-9

d=3

a+d =12+3=15,a=12,a-d=12-3=9