Question

The product of two 2-digit natural numbers is 1938.if the product of their ones digit is 28 and that of their tens digit is 15,find the numbers.

Answer 1

Answer:

37 and 54

Step-by-step explanation:

Let the numbers be ab and xy, where a and x are the tenth place digits and b and y are the oneth place digits.

ab * xy = 1998

ax = 15

Only 5 and 3 are single digit numbers that yield the result 15

by = 28

Only 7 and 4 are single digit numbers that yield the result 28.

The units have to 7 and 4 and the tenth place digits are 5 and 3.

so the number is 57 * 34 or 37 *54

Of theise only 37 * 54 = 1998.

Therefore, the two numbers are 37 and 54.