The product of two 2digit number is 1938. if the product of their units digit is 28 and that of their tens digit is 15 find the number
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Let the numbers be ab and xy, where a and x are the tenth place digits and b and y are the oneth place digits.
ab × xy = 1998
ax = 15
Only 5 and 3 are single digit numbers that yield the result 15
by = 28
Only 7 and 4 are single digit numbers that yield the result 28.
The units have to 7 and 4 and the tenth place digits are 5 and 3.
so the number is 57 × 34 or 37 ×54
Of theise only 37 × 54 = 1998.
Therefore, the two numbers are and
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