Question

the product of two alternate odd integers exceeds three times the smaller by 12 what is the larger number?​

Answer 1

Answer:

7

Step-by-step explanation:

Let two alternate odd integers be (2x+1) and (2x+5).

Then according to the question,

(2x + 1) (2x + 5) = 3(2x + 1) + 12

=> (2x + 1) (2x + 5 - 3) = 12

=> 2x^2 + 3x - 5 = 0

On solving this quadratic equation, we get

x = 1 as integer solution.

Then,

larger integer = 2x + 5 = 2 x 1 + 5 = 7

Answer 2

Answer:

Step-by-step explanation:

let the first odd number be x. And alternate odd no. Is x+4.

x(x+4) =3x+12 . X square + x-12= 0. Then x=3.so,x+3=4+3=