The Product of two conaecutive natural numbers is 42.Find the numbers.
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Let two consecutive no. be x and x+1
A.T.Q-
X(x+1)=42
X²+x=42
x²+x-42=0
x²+7x-6x-42=0
X(x+7)-6(x+7)=o
(x+7)(x-6)=0
X=-7 and x=6
Rejecting x=-7
Hence the number are 6and7
A.T.Q-
X(x+1)=42
X²+x=42
x²+x-42=0
x²+7x-6x-42=0
X(x+7)-6(x+7)=o
(x+7)(x-6)=0
X=-7 and x=6
Rejecting x=-7
Hence the number are 6and7
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