Question

The product of two consecutive even intergers is 128 . From the quadratic equation to find the intergers .
a) x2 + 2x -128=0

Answer 1

Answer:

QUADRATIC EQUATION

LET THE FIRST NO. BE X

SECOND NO. BE X + 2

X ( X + 2 ) = 128

X SQUARE + 2X = 128

X TO THE POWER 2 + 2X = 128

THIS WILL BE YOUR QUADRATIC EQUATION

Answer 2

$let \: the \: first \: consecutive \: number \: = x \\ and \: second \: consecutive \: number \: = x + 1 \\ then \: the \: product \: of \: two \: consecutive \: number = x(x + 1) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = x^{2} + x \\ A.T.Q \\ x^{2} + 1 = 128 \\ x ^{2} + x - 128 = 0$

so, the quadratic equation of this question is :-

$x^{2} + x - 128 = 0$

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