the product of two consecutive even natural numbers is 120 find the numbers
Answers
Answered by
280
Let the numbers be x and x+2.
As per given condition:-
x (x+2) = 120
x^2 +2x - 120 = 0
x^2 +12x-10x -120 = 0
x (x+12) -10 (x+12) = 0
(x+12)(x-10) = 0
x = -12 & 10
When x = -12
The numbers are
x = -12 &
x +2 = -12+2
= -10
When x = 10
Then numbers are
x = 10
x+2 = 12
Please mark it brainliest.
As per given condition:-
x (x+2) = 120
x^2 +2x - 120 = 0
x^2 +12x-10x -120 = 0
x (x+12) -10 (x+12) = 0
(x+12)(x-10) = 0
x = -12 & 10
When x = -12
The numbers are
x = -12 &
x +2 = -12+2
= -10
When x = 10
Then numbers are
x = 10
x+2 = 12
Please mark it brainliest.
Answered by
37
Answer:
Therefore the numbers are 10 and 12
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