Question

the product of two consecutive even natural nuo is 120 find the numbers​

Answer 1

let the numbers be n and n+2.

Then,

(n)(n+2)=120

n^2 + 2n =120

${n}^{2} + 2n - 120 = 0$

${n}^{2} + 12n - 10n - 120 = 0$

$n(n + 12) - 10(n + 12) = 0$

so n can be 10 or -12

and then the numbers are

•10and 12

hope it helped