Question

The product of two consecutive integers is 3,906. Find the integers.
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Answer 1

Answer:

I HOPE ITS HELPFUL.

Answer 2

Let one number be x and the consecutive number is therfore x + 1

Product = x(x+1)

3,906= ×^2 + x

x^2 + x - 3906 = 0

× = [- b +/-root of (b^2 - 4ac)/]2a

= [-1 +/- root of (1^2 - 4 × 1 × - 3906)]/2× 1

= [-1 +/- root of (1 + 15624)]/2

= [-1 +/- root of 15625]/2

= [-1 +/- 125]/2

x = (-1 + 125)/2 and x = (-1 -125)/2

= 124/2 x = -126/2

= 62 x = -63

When x = 62, x + 1 = 63

62 × 63 = 3906

Therefore the numbers are 62 and 63

Hope it helps