the product of two consecutive integers is 56 find the integers
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Let the first integer be x.
Since the integers are consecutive, they have to be x and (x+1).
(x)*(x+1) = 56
x² + x - 56 = 0
x² + 8x - 7x - 56 = 0
x (x+8) - 7 (x+8) = 0
(x-7) (x+8) = 0
x-7 = 0 or x+8 = 0
x = 7 or x = -8
If x = 7,
then, x+1 = 7+1 = 8
The integers are 7 and 8
If x = -8,
then, x+1 = -8+1 = -7
The integers are -7 and -8
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