Question

the product of two consecutive integers is 600. then, the sum of their squares is

Answer 1

Answer:

1201

Explanation:

Let x,(x+1) are two consecutive

integers.

According to the problem given,

x(x+1) = 600

=> x(x+1)=24(24+1)

compare both sides ,we get

x = 24,

x+1 = 24+1 = 25

Now ,

sum of squares of integers

= 24² + 25²

= 576 +625

= 1201

••••