Math, asked by yogeswa6097, 10 months ago

The product of two consecutive integers is divisible by 2.is this statement true or false.justify your answer

Answers

Answered by squeen123
0

Answer:

TRUE

Step-by-step explanation:

t is true that product of two consecutive +ve integers is divisible by 2 as because of the following reasons:-

Let u consider two consecutive +ve integer as n and another as n-1.

Now, the product of both is n2-n

Case 1

When n=2q ( Since any +ve integer can be in the form of 2q or 2q+1)

n2-n= (2q)2-2q

= 4q2- 2q

It is divisible by 2 as it leaves a remainder 0 after division.

Case 2

When n= 2q+1

n2-n = (2q+1)2 - 2q+1

= 4q2+ 4q+2q+2

= 4q2+ 6q+2

It is divisible by 2

So, in both the case of the consecutive integers, it is divisible by 2

Answered by karishma1514
8

Answer:

Your answer is True....

hope it helps...you..

reason --look in attached pic above..

hope it helps ..mark brainliest plz..

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