The product of two consecutive integers is divisible by 2.is this statement true or false.justify your answer
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Answer:
TRUE
Step-by-step explanation:
t is true that product of two consecutive +ve integers is divisible by 2 as because of the following reasons:-
Let u consider two consecutive +ve integer as n and another as n-1.
Now, the product of both is n2-n
Case 1
When n=2q ( Since any +ve integer can be in the form of 2q or 2q+1)
n2-n= (2q)2-2q
= 4q2- 2q
It is divisible by 2 as it leaves a remainder 0 after division.
Case 2
When n= 2q+1
n2-n = (2q+1)2 - 2q+1
= 4q2+ 4q+2q+2
= 4q2+ 6q+2
It is divisible by 2
So, in both the case of the consecutive integers, it is divisible by 2
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Answer:
Your answer is True....
hope it helps...you..
reason --look in attached pic above..
hope it helps ..mark brainliest plz..
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