Math, asked by aakshna122005, 8 months ago

The product of two consecutive multiples of 3 is 108 Find the consecutive terms

Answers

Answered by Anonymous
6

Step-by-step explanation:

x(x+3)=108

x^2+3x-108=0

x^2+12x-9x-108=0

x(x+12)-9(x+12)=0

(x+12)(x-9)=0

x=-12,x=9

Answered by Anonymous
1

Step-by-step explanation:

let the two consecutive multiples of 3 be :

3x,3x+3

3x×3x+3x×3=108

9x^2+9x=108

9x(x+1)=108

x(x+)=12

x^2

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