The product of two consecutive multiples of 3 is 108 Find the consecutive terms
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Answered by
6
Step-by-step explanation:
x(x+3)=108
x^2+3x-108=0
x^2+12x-9x-108=0
x(x+12)-9(x+12)=0
(x+12)(x-9)=0
x=-12,x=9
Answered by
1
Step-by-step explanation:
let the two consecutive multiples of 3 be :
3x,3x+3
3x×3x+3x×3=108
9x^2+9x=108
9x(x+1)=108
x(x+)=12
x^2
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