Question

The product of two consecutive multiples of 4 is 192. what are the numbers?​

Answer 1

Let the two consecutive multiples of 4 be

• 4x
• 4x + 4

$4x(4x + 4) = 192 \\ \\ 16 {x}^{2} + 16x = 192 \\ \\ .......dividing \: both \: sides \: by \: 16. \\ \\ {x}^{2} + x = 12 \\ \\ {x}^{2} + x - 12 = 0 \\ \\ {x}^{2} + 4x - 3x - 12 = 0 \\ \\ x(x + 4) - 3(x + 4) = 0 \\ \\ (x - 3)(x +4 ) = 0 \\ \\ \sf\large\green{\underline { x = 3............x = - 4}}$

1) Numbers are ,

• 4x = 4(3) = 12
• 4x + 4 = 4(3) + 4 = 16

$\sf\large\red{ or}$

2) Numbers are

• 4x = 4(-4) = -16
• 4x + 4= 4(-3) +4 = -12

Answer 2

12,16

12×16= 192

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