Question

The product of two consecutive multiples of 6 is 432. Which are the numbers..

Plz explain.

Answer 1

Step-by-step explanation:

let the two numbers be x and x+6

x(x+6)=432

x^2+6x=432

(x+3)^2=432+9

x+3^2=441

x+3=+or - 21

x=21-3=18

x=-21-13=24

the value of x are 18 and 24

Answer 2

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Let the two numbers be x and x+6

$= > x(x + 6) = 432$

$= > {x}^{2} + 6x = 432$

$= > ({x + 3})^{2} = 432 + 9$

$= > ( {x + 3})^{2} = 441$

$= > x + 3 = 21$

$= > x = 21 - 3$

$= > x = 18$

$x + 6 = > 18 + 6$

$x = 18 \: and \: \: 24$