Question

The product of two consecutive multiples of 8 is 2688. Find the numbers.​

Answer 1

Answer:

According to the conditions ;

( 8x ) ( 8x + 8 ) = 2688

64x^2 + 64x = 2688

32x^2 + 32 x = 1344

16x^2 + 16x = 672

8x^2 + 8x = 336

4x^2 + 4x = 168

2x^2 + 2x = 84

x^2 + x = 42

x^2 + x - 42 = 0

x^2 + 7x - 6x - 42 = 0

x ( x + 7 ) - 6 ( x + 7 ) = 0

( x + 7 ) ( x - 6 ) = 0

therefore;

x = 6 and x = -7

As number canot be in negative si we take x = 6

first term is 6 and second term is 7 ..

(6×8) × (7 × 8 )

= 48 × 56

= 2688

hope it helps

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Answer 2

Step-by-step explanation:

suppose two consecutive numbers are x, x+1.

=> two consecutive multiples of 8 is 8x, 8(x+1)

=> there multiplication = 2688

=> 8x*8(x+1) = 2688

=> 64*x(x+1) = 2688

=> x*(x+1) = 2688/64

=> x*(x+1) = 42

=> x*(x+1) = 6*7

=> x=6

so that numbers are = 8x = 8*6 = 48

and = 8(x+1) = 8(6+1) = 8*7 = 56

=> 48,56