Math, asked by ovi96, 2 months ago

The product of two consecutive natural number is 31 less than the sum of their squares. Find the number​

Answers

Answered by HAZZARD
2

Answer:

Let two consecutive natural numbers be xx and x+1x+1.

Sum of these numbers

=x+x+1=x+x+1

=2x+1=2x+1

Difference of their squares (from largest)

=(x+1)2−x2=(x+1)2−x2

=x2+2x+1−x2=x2+2x+1−x2

=2x+1=2x+1

∴∴ Both are equal.

So the answer is also 31.

Thanks.

HOPE IT HELPED U

THANK U

Answered by kalyanipeddoju862
0

Answer:

let first number =x,second number=x+1

Step-by-step explanation:

the product of two consecutive natural numbers is 31 less than their sum of squares

so

x(x+1)= x square+ ( x+1) whole square-31

x square+ x= 2x square+2x+1-31

2x square- x square+ 2x-x+1-31

x square+x-30=0

x square+6x-5x-30=0

x(x+6)-5(x+6)=0

(x-5),(x+6)=0,x=5;x+1=6

Similar questions