Question

the product of two consecutive natural numbers which are multiples of 3 is equal to 810. find the two numbers.​

Answer 1

Answer:

Numbers are 27 and 30

Step-by-step explanation:

Let the two consecutive natural numbers which are multiples of 3 be x and x+3.

According to the question,

x(x+3) = 810

→ x² + 3x = 810

→ x² + 3x = 810

→ x² + 3x - 810 = 0

→ x² + 30x - 27x - 810 = 0

→ x (x + 30) - 27 (x + 30) = 0

→ (x + 30) (x - 27) = 0

→ x + 30 = 0 or x - 27 = 0

→ x = - 30 or x = 27

∴ x = 27 (∵ -30 is not a natural number)

∴ x + 3 = 27 + 3 = 30

Hence, the two numbers are 27 and 30.

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