the product of two consecutive negative integers is 1122 what is the least number among the two
Answers
Answered by
5
Answer:
Answer:
−
34
,
and
,
−
33
.
Explanation:
As we need two consecutive integers, let us suppose that, these
are
x
and
x
+
1
,
where,
x
and
(
x
+
1
)
<
0
.
By what is given,
x
(
x
+
1
)
=
1122
.
∴
x
2
+
x
=
1122
.
Multiplying by
4
,
we get,
4
x
2
+
4
x
=
4488
.
Completing the square, we have,
4
x
2
+
4
x
+
1
=
4489
.
(
2
x
+
1
)
2
=
67
2
.
2
x
+
1
=
±
67
.
∵
x
<
0
,
&
,
(
x
+
1
)
<
0
;
∴
x
+
(
x
+
1
)
=
2
x
+
1
<
0
.
∴
2
x
+
1
=
−
67
⇒
2
x
=
−
67
−
1
=
−
68
.
∴
x
=
−
34
,
and
,
x
+
1
=
−
33
.
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