The product of two consecutive numbers is 506, what are the numbers (Hint: the numbers are above 20 as 20 X 20= 400 and below 25)
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Answered by
21
Hi ,
Let x , ( x + 1 ) are two consecutive
numbers .
According to the problem given ,
Product of given numbers = 506
x( x + 1 ) = 506
x² + x - 506 = 0
Splitting the middle term , we get
x² + 23x - 22x - 506 = 0
x( x + 23 ) - 22( x + 23 ) = 0
( x + 23 ) ( x - 22 ) = 0
x + 23 = 0 or x - 22 = 0
x = -23 or x = 22
Therefore ,
Required two numbers are ,
x = 22 ,
x + 1 = 22 + 1 = 23
I hope this helps you.
: )
Let x , ( x + 1 ) are two consecutive
numbers .
According to the problem given ,
Product of given numbers = 506
x( x + 1 ) = 506
x² + x - 506 = 0
Splitting the middle term , we get
x² + 23x - 22x - 506 = 0
x( x + 23 ) - 22( x + 23 ) = 0
( x + 23 ) ( x - 22 ) = 0
x + 23 = 0 or x - 22 = 0
x = -23 or x = 22
Therefore ,
Required two numbers are ,
x = 22 ,
x + 1 = 22 + 1 = 23
I hope this helps you.
: )
Answered by
2
Let x , ( x + 1 ) are two consecutive
numbers .
According to the problem given ,
Product of given numbers = 506
x( x + 1 ) = 506
x² + x - 506 = 0
Splitting the middle term , we get
x² + 23x - 22x - 506 = 0
x( x + 23 ) - 22( x + 23 ) = 0
( x + 23 ) ( x - 22 ) = 0
x + 23 = 0 or x - 22 = 0
x = -23 or x = 22
Therefore ,
Required two numbers are ,
x = 22 ,
x + 1 = 22 + 1 = 23
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