Question

- "The product of two consecutive odd integers is 35. For the equation
11​

Answer 1

Answer:

let the two consecutive numbers be x and x+2

according the question,

x(x+2)=35

x²+2x=35

or we can write x²+2x-35=0 is the equation

and the factors of this question is here,

x²+(7-5)x-35=0

x²+7x-5x-35=0

x(x+7) -5(x+7)=0

(x+7) (x-5) is the factors

so you can put the value of these in x and X+2

Answer 2

Step-by-step explanation:

let the two odd integers be (x+1) and (x+3)

according to given condition,

(x+1)(x+3)=35

so x square+4x+3=35

so then

x square+4×-32

solve it you get x=-8 or x=4

but as it is odd integers negative nos are unacceptable

so x=-8 is absurd so x=4

substitute value of in x+1 and x+3

so the integers are 5 and 7

verify it

so 5×7=35

thus 35=35

so lhs=rhs

hence verified