Question

the product of two consecutive odd integers is equal to 2499 find the two integer​

Answer 1

Answer:

Let first odd number be x.

Second odd number= x+2

⇒ x+ (x+2)= 2499

= 2x+ 2= 2499

= 2x= 2497

Your statement is incorrect because the sum of 2 odd numbers is always even but acc to your statement, the sum has to be 2499, which is an odd number. So please recheck your question.

Answer 2

Given :

• The product of two consecutive odd integers is equal to 2499.

To find :

• The two integers =?

Step-by-step explanation :

Let, the first consecutive odd integers be, x.

Then, the second consecutive odd integer be, x + 2.

It is Given that,

The product of two consecutive odd integers is equal to 2499.

According to the question,

➟ x(x + 2) = 2499

➟ x² + 2x = 2499

➟ x² + 2x - 2499 = 0

➟ x² + 51x - 49x - 2499 = 0

➟ (x² + 51x) + ( - 49x - 2499) = 0

➟ x(x + 51) - 49 (x + 51) = 0

➟ (x + 51) (x - 49) = 0

Now,

x + 51 = 0

x = - 51. [Ignore negative]

So,

x - 49 = 0

x = 49.

Therefore, We got the value of, x = 49.

Hence,

The first consecutive odd integers , x = 49

Then, the second consecutive odd integer , x + 2 = 49 + 2 = 51