Question

the product of two consecutive odd integers is equal to 675 find the two integers​

Answer 1

Answer:

25,27 or -27,-25

Step-by-step explanation:

Let the two integers be n and n+2

ATP,

=>n(n+2)=675

=>n²+2n-675=0

=>n²+27n-25n-675=0

=>n(n+27)-25(n+27)=0

=>(n-25)(n+27)=0

=>n=25, or,, -27

Therefore, the no.s are 25,27 or, -27,-25.

Answer 2

Given :

• The product of two consecutive odd integers is equal to 675.

To find :

• The two integers =?

Step-by-step explanation :

Let, the first consecutive odd integers be, x.

Then, the second consecutive odd integer be, x + 2.

It is Given that,

The product of two consecutive odd integers is equal to 675.

According to the question,

➟ x(x + 2) = 675

➟ x² + 2x = 675

➟ x² + 2x - 675 = 0

➟ x² + 27x - 25x - 675 = 0

➟ (x² + 27x) + (-25x - 675) = 0

➟ x(x + 27) - 25 (x + 27) = 0

➟ (x + 27) (x - 25) = 0

Now,

x + 27 = 0

x = - 27. [Ignore negative]

So,

x - 25 = 0

x = 25.

Therefore, We got the value of, x = 25.

Hence,

The first consecutive odd integers , x = 25.

Then, the second consecutive odd integer , x + 2 = 25 + 2 = 27