the product of two consecutive odd no. is 63 .find the no.
Answers
First number: x
Second number: x + 2
Make an equation and solve it,
x(x + 2) = 63
x² + 2x = 63
x² + 2x - 63 = 0
Factorise the equation,
(x - 7)(x + 9) = 0
x - 7 = 0
x = 7
x + 9 = 0
x = -9
So there are two answers for x: 7 and -9.
Now find x + 2, which will have two answers also.
7 + 2 = 9 [First answer]
-9 + 2 = -7 [Second answer]
Therefore, to answer your question, the numbers are 7 and 9 (or -9 and -7).
Answer:
This question can have two answers which are as follows -
1. - 9 and - 7
2. 7 and 9
Step-by-step explanation:
Since the consecutive odd number differ by 2, we may assume the numbers as follow:
First Consecutive Odd Number, m = ' x '
Second Consecutive Odd Number, n = ' x + 2 '
Hence on reading the question carefully we may derive the following relation :
m * n = 63
x * ( x + 2 ) = 63
Simplifying further,
x ^ 2 + 2x = 63
x ^ 2 + 2x - 63 = 0
x ^ 2 + 9x - 7x - 63 = 0
x ( x + 9 ) - 7 ( x + 9 ) = 0
( x + 9 ) ( x - 7 ) = 0
By zero product rule,
=> x + 9 = 0 OR => x - 7 = 0
=> x = - 9 OR => x = 7
Taking x = - 9,
First Consecutive Odd Number = - 9
Second Consecutive Odd Number = ( - 9 + 2 ) = - 7
Taking x = 7,
First Consecutive Odd Number = 7
Second Consecutive Odd Number = ( 7 + 2 ) = 9