the product of two consecutive odd number is 19043. which is the smaller number.
a. 137
b. 131
C. 133
d. 129
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Answered by
0
(2n+1) (2n+3) = 19043
137
137
Answered by
1
Let the two numbers be x and x + 2
Produc5 of two consecutive numbers = 19043
x ( x + 2) = 19043
x^2 + 2x = 19043
x^2 + 139x - 137x - 19043 = 0
x ( x + 139) - 137(x + 139) = 0
(x - 137)(x + 139) = 0
X = 137
Ans. The two consecutive numbers = 137 and 139
The smaller number = 137
Produc5 of two consecutive numbers = 19043
x ( x + 2) = 19043
x^2 + 2x = 19043
x^2 + 139x - 137x - 19043 = 0
x ( x + 139) - 137(x + 139) = 0
(x - 137)(x + 139) = 0
X = 137
Ans. The two consecutive numbers = 137 and 139
The smaller number = 137
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