Question

the product of two consecutive odd numbers is 10 more than the square of the smaller number. Find the smaller number

Answer 1

Answer: 5

Step-by-step explanation:

x (x + 2) = x^2 + 10

x^2 + 2x = x^2 +10

2x = 10

(2x = 10) / 2

x = 5

Answer 2

Answer: The correct answer is 5

Step-by-step explanation:

Let the odd number be x and  the consecutive odd number be x + 2

Now it is given that the product of two consecutive odd numbers is 10 more than the square of the smaller number among them

So now the smaller number is x among x and x + 2

According to the question,

product of two consecutive odd numbers is 10 more than the square of the smaller number among them

So,
⇒ x ( x+2 ) - x² = 10

⇒ x² + 2x - x² = 10

⇒ 2x = 10

⇒ x = 5

Thus the odd number = 5

Other odd number = x + 2 =  5+2 = 7

Hence, the smaller number is 5.

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