the product of two consecutive odd numbers is 483 .find the numbers
Answers
Answered by
33
Heya!!!
Let the two consecutive odd numbers be 'x+1' and 'x+3'
Given :
(x+1)(x+3) = 483
= x^2 + 3x + x + 3 = 483
= x^2 + 4x -480 = 0
=Let's solve your equation step-by-step.
x^2+4x−480=0
Step 1: Use quadratic formula with a=1, b=4, c=-480.
x=−b±√b2−4ac2a
x=−(4)±√(4)2−4(1)(−480)2(1)
x=−4±√19362
x=20 or x=−24
So the possible pairs of consecutive odd numbers are :
(21 , 23)
(-23 , -21)
HOPE IT HELPS!
Let the two consecutive odd numbers be 'x+1' and 'x+3'
Given :
(x+1)(x+3) = 483
= x^2 + 3x + x + 3 = 483
= x^2 + 4x -480 = 0
=Let's solve your equation step-by-step.
x^2+4x−480=0
Step 1: Use quadratic formula with a=1, b=4, c=-480.
x=−b±√b2−4ac2a
x=−(4)±√(4)2−4(1)(−480)2(1)
x=−4±√19362
x=20 or x=−24
So the possible pairs of consecutive odd numbers are :
(21 , 23)
(-23 , -21)
HOPE IT HELPS!
Answered by
2
yes the above ans is correct and really helpful (・∀・)
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