Question

The product of two consecutive odd numbersin 6723. What is the square root of the smallernumber?

Answer 1

Given →

The product of two consecutive odd numbers is 6723 .

To find →

Square root of smaller number .

Answer →

9 is the required number. As smaller number is 81 .So square root of 81 is 9 .

Solution→

Let the two odd numbers as x and x+2

Now A/q :

x( x+2) = 6723

x² + 2x = 6723

x² + 2x + 6723 = 0

Here we got a quadratic equation . So by using quadratic formula we will find the value of x.

Quadratic formula= - b +/-( √ b²-4ac) / 2a

here a= 1, b = 2 ,c = -6723.

→ [-2 +/- √ 2² - 4 (1)(-6723)]/2

→ -2+/-(√4+26892)/2

→ -2 +/-(164)/2

Now using +ve term

→ -2 +164 / 2

→ 162/ 2 = 81

So x = 81 and x+2 = 83

Smaller number = 81

Square root of 81 = 9