Question

The product of two consecutive position integers is 306 find the integers

Answer 1

Answer:

Therefore two consecutive positive integers are 17 and (17 + 1 = 18) whose product is 306. Therefore the smallest positive integer is 17. So this is the required answer.

Explanation:

Let integers be n and (n+1)

n(n+1)=306

n

2

+n−306=0

(n+17)(n−16)=0

Therefore, n=16 and integers are 16 and 17.

Hope it helps you