Question

the product of two consecutive position intergers is 72. find the integers.

Answer 1

Hey

$x(x + 1) = 72$

$= > ( {x}^{2} + x - 72) = 0$

$= > (x + 9)(x - 8) = 72$

Hence, you get the positive integers as :

$8 \: and \: 9$

Answer 2

I hope it will help u
the integers are x and(x+1)=72
x²+x=72
x²+x-72=0
(x+9) (x-8)=72
hence the numbers are 8 and 9