the product of two consecutive positive integer is 306 we need to find the integers
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Answered by
2
The integers are....
1 ) 17......
2 ) 18....
Let integers are x , X+1
( x) (x+1) = 306.
x^2 + x - 306 = 0
x^2 + 18 x - 17 x -306. = 0
x ( x + 18 ) -17 ( x + 18 ) = 0
( x + 18 ). ( x -17 )
X = -18 , 17
as integers are positive therefore , negelecting -18...
The integers are ....
X = 17
X + 1 = 18 ...
Hope it helps to you.....
please mark it as brainliest answer if helpful...please please please
1 ) 17......
2 ) 18....
Let integers are x , X+1
( x) (x+1) = 306.
x^2 + x - 306 = 0
x^2 + 18 x - 17 x -306. = 0
x ( x + 18 ) -17 ( x + 18 ) = 0
( x + 18 ). ( x -17 )
X = -18 , 17
as integers are positive therefore , negelecting -18...
The integers are ....
X = 17
X + 1 = 18 ...
Hope it helps to you.....
please mark it as brainliest answer if helpful...please please please
Answered by
1
Let us consider,
The first integer number = x
Thus, the next consecutive positive integer will be = x + 1
Product of two consecutive integers = x × (x +1) = 306
⇒ x2 + x = 306
⇒ x2 + x – 306 = 0
Therefore, the two integers x and x+1, satisfies the quadratic equation, x2 + x – 306 = 0, which is the required representation of the problem mathematically.
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