The product of two consecutive positive integer is 306 write suitable quadratic equation for the above situation.
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Given:
The product of two successive positive integers is 306.
To Find:
We have to write a suitable quadratic equation for the above situation.
Concept Used:
We will make use of assumption of two successive integers as x and x+1.
Answer:
Let us suppose the two consecutive integers as x & x+1 .
By question we have to multiply these.
So,this will give us,
(x+1)x
And this equals to 306.
Equating these,
=> x(x+1) =306.
=> x²+x =306.
.°. x²+x-306 = 0 .
.°. The suitable quadratic equation will be x² +x-306 =0
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