Question

the product of two consecutive positive integer is a 306 we need find that year

Answer 1

HEY MATE HERE IS YOUR ANSWER

Let the two consecutive positive integers be
X and x+1
Product =306
x (x+1)=306
${x}^{2} + x = 306 \\ {x}^{2} + x - 306 = 0 \\ we \: should \: factorise \: the \: equation \\ {x}^{2} + 18x - 17x - 306 = 0 \\ x(x + 18) - 17( x + 18) \\ (x - 17)(x + 18) \\ then \: the \: two \: valuse \: of \: x \: we \: get \: is \: 17or - 18 \\ but \: we \: know \: that \: it \: is \: two \: positive \: integers \: \\ so \: the \: consecutive \: no \: are \: 17and18$
HOPE IT HELPS YOU

FOLLOW ME FOR ANY OTHER QUESTIONS

Answer 2

the number are 17&18
dear friend