the product of two consecutive positive integers is 210.find the two integers.
Attachments:
Answers
Answered by
4
Let the 1 consecutive no. be x
2nd consecutive no. =x+2
(as they are positive
consecutive nos.)
Their sum =210
So, - x+x+2=210
2x+2=210
2x=208
X=208/2
=104
X=104.
. .&
x+2 =104 +2 =106
Hence,nos. are 104 & 106.
Hope this will help u...
2nd consecutive no. =x+2
(as they are positive
consecutive nos.)
Their sum =210
So, - x+x+2=210
2x+2=210
2x=208
X=208/2
=104
X=104.
. .&
x+2 =104 +2 =106
Hence,nos. are 104 & 106.
Hope this will help u...
Ranjan14082002:
Its wrong bro....
Answered by
8
Let 1st no. be x and 2nd no. be x+1,
(As they are consecutives)
Here, ATQ,
x*x+1=210
x2+x=210
x2+x-210=0
By split term method,
x2+15x-14x-210=0
x(x+15)-14(x+15)=0
(x+15)*(x-14)=0
So,
x=14,or-15
Since,
x=14
So, x+1=15
That is, 1st no. =14
2nd no. =15
(As they are consecutives)
Here, ATQ,
x*x+1=210
x2+x=210
x2+x-210=0
By split term method,
x2+15x-14x-210=0
x(x+15)-14(x+15)=0
(x+15)*(x-14)=0
So,
x=14,or-15
Since,
x=14
So, x+1=15
That is, 1st no. =14
2nd no. =15
Similar questions