The product of two consecutive positive integers is 306. Find the two integers.
Class 10th
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but it was not full solution thats why i said utsav100 to delete this and answer
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Answered by
57
x = 17
x = - 18
Let x and x + 1 be the two consecutive positive integers .
Then, x(x + 1) = 306
→ x² + x - 306 = 0.
→ x² + 18x - 17x - 306 = 0.
→ x ( x + 18 ) - 17 ( x + 18 ) = 0
→ ( x - 17 ) ( x + 18 ) = 0.
→ x - 17 = 0
→ x = 17
and
→ x + 18 = 0
→ x = -18
Rejecting x = -18 , as the given numbers are positive , we get x = 17
•°• The two integers are 17 and 18.
Answered by
19
HELLO DEAR
given the product of two consecutive positive integers is 306.
let the one integer be x
and hence another be x+1
atq, x(x+1) = 306
x² + x = 306
x² + x - 306 = 0
x² + 18x - 17x - 306 = 0
x(x+18) -17(x+18)
(x-17)(x+18)
x = 17 [since integer must be positive ]
so one number is 17
and another will be 17 + 1 = 18
THANKS
given the product of two consecutive positive integers is 306.
let the one integer be x
and hence another be x+1
atq, x(x+1) = 306
x² + x = 306
x² + x - 306 = 0
x² + 18x - 17x - 306 = 0
x(x+18) -17(x+18)
(x-17)(x+18)
x = 17 [since integer must be positive ]
so one number is 17
and another will be 17 + 1 = 18
THANKS
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