The product of two consecutive positive integers is 306.we need to find the integers
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Answer:
Step-by-step explanation:
Let the two integers be x and x+1
Product=306
X(x+1)=306
X^2+x=306
x^2+x-306=0
By spliting the middle term
(X+18)(x-17)=0
X=-18,x=17
We want
Positive integer so x=17
X+1=17+1=18
The two numbers are 17 and 18.
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Answered by
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Let the two consecutive numbers be x and x+1
According to question=>
(Thier product =306)
(x)(x+1)=306
x²+x=306
x²+x-306=0
Now, solving by middle spliting method<=>
=>x²+18x-17x-306=0
=>x(x+18)-17(x+18)=0
=>(x-17)(x+18)=0
=>x-17=0 , x+18=0
=>x=17 , x=-18(Rejected)
[-18 is rejected because positive integer cannot be in negative value]
Therefore,x=17
x+1=17+1=18
Therefore, two positive integers are 17 and 18
HOPE IT IS HELPFUL,
PLS MARK IT AS BRAINLIEST!!!!
According to question=>
(Thier product =306)
(x)(x+1)=306
x²+x=306
x²+x-306=0
Now, solving by middle spliting method<=>
=>x²+18x-17x-306=0
=>x(x+18)-17(x+18)=0
=>(x-17)(x+18)=0
=>x-17=0 , x+18=0
=>x=17 , x=-18(Rejected)
[-18 is rejected because positive integer cannot be in negative value]
Therefore,x=17
x+1=17+1=18
Therefore, two positive integers are 17 and 18
HOPE IT IS HELPFUL,
PLS MARK IT AS BRAINLIEST!!!!
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