Question

The Product of two consecutive positive multiples of 3 is 810.Find the numbers.

Answer 1

Let the multiples be 3x and 3 (x+1)
3x×(3x+3)=9x^2+9x
9x^2+9x=810
I think you can find it now

Answer 2

Answer :

Two numbers are 27 and 30.

Step by step explanation :

Hey Mate,

Suppose, The two numbers are ( 3X ) and ( 3X + 3  )

So,

3X( 3X + 3 ) = 810  

X( 3X + 3 ) = 810  / 3

X( 3X + 3 ) = 270

3X² + 3X  = 270

3( X² + X )  = 270

( X² + X )  = 270/3

( X² + X )  = 90

X² + X - 90 = 0

X² + 10X - 9X - 90 = 0

X ( X + 10 ) -9 ( X + 10 ) = 0

X = +9 and -10

Always take positive value of X. So, X = 9

Put the value of X in ( 3X ) and ( 3X + 3  )

So,

Two  numbers are (3 × 9) and ( 3 × 9 + 3 )

Two numbers are 27 and 30.

#Recheck : 27 × 30 = 810.