The Product of two consecutive positive multiples of 3 is 180.Find the numbers.
Answers
Answered by
35
Let the no be 3x, 3(x+1)
since the product is 180
so
3x ×3(x+1)= 180
9x(x+1)=180
x(x+1)= 20
or
(x+5)(x-4)=0
x=4
so the no are 12,15
since the product is 180
so
3x ×3(x+1)= 180
9x(x+1)=180
x(x+1)= 20
or
(x+5)(x-4)=0
x=4
so the no are 12,15
Answered by
4
Given,
The product of two consecutive positive multiples of 3 is 180.
To find,
We have to find the numbers which are consecutive positive multiples of 3.
Solution,
The positive consecutive numbers which are multiples of 3 whose Product is 180 are 12 and 15.
Let the numbers be 3x and 3x +3
According to the given condition, the product of the two numbers = 180
3x(3x+3) = 180
Using distributive property,
9x² + 9x -180
Taking 9 commons, the quadratic equation reduces to,
x² + x-20
x² +5x-4x-20
x(x+5)-4(x+5)
(x+5)(x-4)
x= -5, x= 4
x = 4
Numbers will be = 3(4)
= 12
= 3(4) +3
= 15
Hence, the positive consecutive numbers which are multiples of 3 whose Product is 180 are 12 and 15.
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