Question

the product of two consecutive positive number is 182,find the number
word problem

Answer 1

Let the numbers be x & x+1.
According to question :-
x (x+1) = 182
x^2 + x = 182
x^2 +x - 182 = 0
x^2 +14x -13x-182 = 0
x (x+14) -13 (x+14) = 0
(x+14) (x-13) = 0
So , x = -14 or 13

But x is a positive number therefore x = 13.

So the numbers are
x = 13 &
x+1 = 13+1
= 14

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Answer 2

Hey Mate !
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Here is your answer :

============================

Given,

product of two numbers = 182

let the numbers be x and x + 1

ATP,

x ( x + 1 ) = 182

${x}^{2} + x = 182 \\ \\ {x}^{2} + x - 182 = 0 \\ \\ after \: splitting \: middile \: term \\ \\ {x}^{2} - 14x + 13x - 182 = 0 \\ \\ x(x - 14) - 13(x - 14) = 0 \\ \\ x - 14 = 0 \: \: \: \: x - 13= 0\\ \\ x = 14 \: \: \: \: \: \: x = 13$

Therefore , the numbers are 13 & 14


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